Why Are Hexadecimal Numbers Automatically Converted To Decimal?

I am working on a little Python method that needs to read a dictionary from another file that will represent the key and values. But it seems I am running into a problem with the r

Solution 1:

Can someone tell me why the values are being represented in decimal form and not in the hexadecimal form that they are originally stored in?

They were not originally stored in hexadecimal. Python does not track any information about base; whether you type 0x1000 or 4096 in your source code, it's the same number, and Python stores it the same way.

When Python prints a number, it has to choose a base to display it in, and the default is always decimal. If you want to print it differently, you will need to specify a different way to perform string conversion, such as the hex function:

>>>print0x1000
4096
>>>printhex(0x1000)
0x1000

Solution 2:

Python stores the numbers the same way, the only thing that changes is the formatting. Your issue is how the numbers are being formatted, not represented, thus, you fix your problem with string formatting:

>>> d = {k:v for k,v inzip('abcdefg',range(1,5000,313))}
>>> d
{'e': 1253, 'g': 1879, 'a': 1, 'd': 940, 'c': 627, 'b': 314, 'f': 1566}
>>> for k,v in d.items():
... print("{} {:#06x}".format(k,v))
... 
e 0x04e5
g 0x0757
a 0x0001
d 0x03ac
c 0x0273
b 0x013a
f 0x061e