Is This A Correct Use Of The `in` Keyword In Python?

I am trying to make a really basic hangman game by using an if/in check, however, the code wasn't responding to changes in the player input. Since this is my first time using the i

Solution 1:

Please check if this code works for you. I modified it a little and added some more conditions.

#put word into here, as a string :)

print("Welcome to Hangman")
word = ["a", "v", "a", "c", "a", "d", "o"]

wordLength = len(word) + 1
lives = wordLength * 2print("lives:", lives)
print("Letters in word", wordLength)

guess = input("Enter the letter : ")

while lives != 0:
    if guess in word:
        print("YES!")
        print(guess)
        index = word.index(guess)
        #print("Index = ",index)
        del word[index]
    else:
        print("Wrong!")
        lives -=1print("lives:", lives)

    if len(word)==0 and lives > 0:
        print("Success!!")
        break
    guess = input("Enter the letter : ")



if lives == 0:
    print("falied! try again")

Solution 2:

Is this a correct use of the in keyword in python?

yes, it's correct to use the in keyword to check if a value is present in a sequence (list, range, string etc.), but your sample code contains several other errors, which are out-of-scope of the main question, just like the game below...

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In the meanwhile, I got interested by the question and coded a quick StackOverflow Popular Tags Hangman game with Tag definitions, i.e:

import requests
from random import choice

# src https://gist.github.com/chrishorton/8510732aa9a80a03c829b09f12e20d9c
HANGMANPICS = ['''
  +---+
  |   |
      |
      |
      |
      |
=========''', '''
  +---+
  |   |
  O   |
      |
      |
      |
=========''', '''
  +---+
  |   |
  O   |
  |   |
      |
      |
=========''', '''
  +---+
  |   |
  O   |
 /|   |
      |
      |
=========''', '''
  +---+
  |   |
  O   |
 /|\  |
      |
      |
=========''', '''
  +---+
  |   |
  O   |
 /|\  |
 /    |
      |
=========''', '''
  +---+
  |   |
  O   |
 /|\  |
 / \  |
      |
=========''']


# english word_list (big)# word_list = requests.get("https://raw.githubusercontent.com/dwyl/english-words/master/words_alpha.txt").text.split("\n")# you can use any word_list, as long as you provide a clean (lowered and sripped) list of words.# To create a hangman game with the most popular tags on stackoverflow, you can use:try:
    word_list = requests.get("https://api.stackexchange.com/2.2/tags?order=desc&sort=popular&site=stackoverflow").json()['items']
    word_list = [x['name'].lower() for x in word_list if x['name'].isalpha()] # filter tags with numbers and symbolsexcept:
    print("Failed to retrieve json from StackExchange.") # exit here# function that returns a random word with/out length range , uses word_listdefrand_word(_min=1, _max=15):
    # filter word_list to words between _min and _max characters
    r_word = [x.strip() for x in word_list if _min <= len(x) <= _max] #return choice(r_word)

# tag definition from stackoverflow wikideftag_info(w):
    try:
        td = requests.get(f"https://api.stackexchange.com/2.2/tags/{w}/wikis?site=stackoverflow").json()['items'][0]['excerpt']
        return(td)
    except:
        passprint(f"Failed to retrieve {w} definition")

# game logic (win/loose)defplay(word):
    word_l = list(word) # list with all letters of word

    wordLength = len(word_l)
    lives = 7print("Lives:", lives)
    print("Letters in word", wordLength)
    place_holder = ["*"for x in word_l]
    used = [] # will hold the user input letters, so no life is taken if letter was already used.while1:
        print("".join(place_holder))
        guess = input().lower().strip() # get user guess, lower it and remove any whitespaces it may haveifnot guess orlen(guess) > 1: # if empty guess or multiple letters, print alert and continueprint("Empty letter, please type a single letter from 'a' to 'z' ")
            continueif guess in word_l:
            used.append(guess) # appends guess to used lettersprint(guess, "Correct!", guess)
            for l in word_l: # loop all letters in word and make them visibleif l == guess:
                    index = word_l.index(guess) # find the index of the correct letter in list word
                    word_l[index] = "."# use index to substitute the correct letter by a dot (.), this way, and if there are repeated letters, they don't  overlap on the next iteration. Small hack but it works.
                    place_holder[index] = guess # make the correct letter visible on place_holder. Replaces * by guesselif guess in used:
            print("Letter already used.")
            continueelse:
            used.append(guess) # appends guess to used lettersprint(HANGMANPICS[-lives])
            lives -= 1# removes 1 lifeprint(f"Wrong! Lives: {lives}" )

        if lives == 0:
            print(f"You Lost! :-|\nThe correct word was:\n{word}\n{tag_info(word)}")
            #print(HANGMANPICS[-1])break# When there are no more hidden letters (*) in place_holder the use won.ifnot"*"in place_holder:
            print(f"You Won!!!\n{word}\n{tag_info(word)}")
            breakprint("Welcome to StackTag Hangman")
while1:
    play(rand_word(1, 15)) # creates a new game with a random word between x and x letters. play() can be simply be used as play("stackoverflow").
    pa = input("Try again? (y/n)\n").lower().strip() # Ask user if wants to play again, lower and cleanup the input for comparision below.if pa != "y": # New game only if user input is 'y', otherwise break (exit)print("Tchau!")
        break

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Notes:

1. You can play with it
2. Asciinema Video
3. v2 with approx. 7k computer jargon's.

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