Aggregate All Dataframe Row Pair Combinations Using Pandas
Solution 1:
I can't think of a clever vectorized way to do this, but unless performance is a real bottleneck I tend to use the simplest thing which makes sense. In this case, I might set_index("Gene")
and then use loc
to pick out the rows:
>>>df = df.set_index("Gene")>>>cc = list(combinations(mygenes,2))>>>out = pd.DataFrame([df.loc[c,:].sum() for c in cc], index=cc)>>>out
case1 case2 control1 control2
(ABC1, ABC2) 1 2 0 1
(ABC1, ABC3) 1 2 1 1
(ABC1, ABC4) 0 1 1 2
(ABC2, ABC3) 2 2 1 0
(ABC2, ABC4) 1 1 1 1
(ABC3, ABC4) 1 1 2 1
Solution 2:
Before going too far, you should keep in mind your data gets big pretty fast. With 5 rows, output will be C(5,2)
or 5+4+3+2+1
and so on.
That said, I'd think about doing this in numpy for speed (you may want to add a numpy tag to your question btw). Anyway, this isn't as vectorized as it might be, but ought to be a start at least:
df2 = df.set_index('Gene').loc[mygenes].reset_index()
import math
sz = len(df2)
sz2 = math.factorial(sz) / ( math.factorial(sz-2) * 2 )
Gene = df2['Gene'].tolist()
abc = df2.ix[:,1:].values
import math
arr = np.zeros([sz2,4])
gene2 = []
k = 0
for i in range(sz):
for j in range(sz):
if i != j and i < j:
gene2.append( gene[i] + gene[j] )
arr[k] = abc[i] + abc[j]
k += 1
pd.concat( [ pd.DataFrame(gene2), pd.DataFrame(arr) ], axis=1 )
Out[1780]:
0 0 1 2 3
0 ABC1ABC2 1 2 0 1
1 ABC1ABC3 1 2 1 1
2 ABC1ABC4 0 1 1 2
3 ABC2ABC3 2 2 1 0
4 ABC2ABC4 1 1 1 1
5 ABC3ABC4 1 1 2 1
Depending on size/speed issues you may need to separate the string and numerical code and vectorize the numerical piece. This code is not likely to scale all that well if your data is big and if it is, that may determine what sort of answer you need (and also may need to think about how you store results).
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