Python - Check If Two Words Are In A String

I would like to check whether 2 words 'car' and 'motorbike' are in each element of an array in Python. I know how to check for one word with in but have no idea how to do with 2 wo

Solution 1:

Two word solution:

forstring in array:
    if'car' in stringand'motorbike' in string.split():
        print("Car and motorbike are in string")

n-word solution to check if all words in test_words are in string:

test_words = ['car', 'motorbike']
contains_all = Trueforstring in array:
    for test_word in test_words:
        if test_word not in string.split()::
            contains_all = Falsebreakif not contains_all:
        breakif contains_all:
    print("All words in each string")
else:
    print("Not all words in each string")

Solution 2:

Use an auxiliar boolean.

car=False
 motorbike=Falsefor elem in array:

        if"car" in elem:
            car=Trueif"motorbike" in elem:
            motorbike=Trueif car and motorbike:
            break

EDIT: I just read "in each element". Just use AND.

Solution 3:

I think a simple solution is this:

all(map(lambda w: w in text, ('car', 'motorbike')))

But there might be a problem with this, depending on how picky you need the comparison to be:

>>> text = 'Can we buy motorbikes in carshops?'>>> all(map(lambda w: w in text, ('car', 'motorbike')))
True

The words 'car' and 'motorbike' are NOT in the text, and this still says True. You might need a full match in words. I would do this:

>>> words = ('car', 'motorbike')
>>> text = 'Can we buy motorbikes in carshops?'>>> set(words).issubset(text.split())
False>>> text = 'a car and a motorbike'>>> set(words).issubset(text.split())
True

And now it works!

Solution 4:

I would use the all function:

wanted_values = ("car", "motorbike")
all(vehicle intextfortextin wanted_values)

So if we have a list of strings:

l = ['some car and motorbike','a motorbike by a car','the car was followed by a motorbike']

lines_with_vehicles = [textfortextin l
                       if all(vehicle intextfortextin wanted_values)]

With regex you could do:

# no particular order
car_and_motorbike_pattern = re.compile(r'(car.*motorbike|motorbike.*car)')
all(car_and_motorbike_pattern.search(text) for text in list_of_expressions)

# This works too
car_or_motorbike_pattern = re.compile(r'(car|motorbike)')
get_vehicles = car_or_motorbike_pattern.findall
all(len(set(get_vehicles(text))) == 2for text in list_of_expressions)

Solution 5:

This link worked for me: It offers 3 solutions. Two methods use list comprehensions and the third one uses map + lambda functions.

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I think there is not an easy and pythonic way to do that. You need to use an ugly logic like the next:

image_file_name = 'man_in_car.jpg'if'car'in image_file_name and 'man'in image_file_name:
    print('"car" and "man" were found in the image_file_name')

That would work for two words, but if you need to check many words, then better use the code in the link above

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I would like to be able to do something like:

if'car' and 'man'in image_file_name:
    print('"car" and "man" were found in the image_file_name')

Or:

if any(['car','man'] in image_file_name):
    print('"car" and "man" were found in the image_file_name')

But these 2 last pieces of code don't work in python (yet).