How To Multiply Each Integer "one By One" And Display Result "in Progressive Order" Until All Integers Multiplied Leads To The Overall Product

Recently, I've tried creating a for loop that multiplies each integer in the list and returns each sequential product until the overall product of all integers is given. import

Solution 1:

You are iterating over the elements of s, not the indexes. Print the list before removing the duplicates, it will be:

[497952, 24, 72, 288, 497952, 497952]
# Whicharetheproductsof:
[s[0:12], s[0:2], s[0:3], s[0:4], s[0:13], s[0:133]]

Replace the first loop by a index loop, either by range(len(s)) or by enumerate(s):

# Either this:
progression_product = [];
for i in range(len(s)):
      progression_product.append(reduce(mul, s[0:i]))

# Or this:
progression_product = [];
for i, v in enumerate(s):
      progression_product.append(reduce(mul, s[0:i]))