Finding The Minimum Of Each Column Of A Csv File Using Python
I've created a program which finds the minimum of each row of a CSV file and I would now like to do the same for each column, however I have been unable to do so. Any advice would
Solution 1:
You could do it with only python built in commands and a transpose achieved by zipping all the rows as follows:
import csv
a = []
withopen('path/to/file.csv',"r") as f:
        reader = csv.reader(f, delimiter=',')
        for row in reader:
            #turn all input to floats
            row = map (float, row)
            #append the entire row to create list of lists
            a.append(row)
# Transpose a into b
b = zip (*a)
# Now min of row will be min of col in afor line in b:
    printmin(line)
Solution 2:
The following should work:
withopen("data.csv", "r") as f_input:
    lmin_col = []
    lmin_row = []
    for row in csv.reader(f_input):
        row = map(float, row)
        lmin_row.append(min(row))
        if lmin_col:
            lmin_col = map(min, lmin_col, row)
        else:
            lmin_col = row
    print"Min per row:", lmin_row
    print"Min per col:", lmin_col
With the following as input:
10.1, 15.6, 12.3, 13.2, 17.0
2.1,  5.3,  7.0,  11.4, 5.5
12.1, 7.0,  9.3,  28.7, 1.0
It gives the following output:
Min perrow: [10.1, 2.1, 1.0]
Min per col: [2.1, 5.3, 7.0, 11.4, 1.0]
Testing using Python 2.7. Below is also a possible alternative version for Python 3.0:
withopen("data.csv", "r") as f_input:
    lmin_col = []
    lmin_row = []
    forrowin csv.reader(f_input):
        row= [float(col) for col inrow]
        lmin_row.append(min(row))
        if lmin_col:
            lmin_col = [min(x,y) for x,y in zip(lmin_col, row)]
        else:
            lmin_col =row
    print("Min per row:", lmin_row)
    print("Min per col:", lmin_col)
Solution 3:
I'd suggest to use np.loadtxt to read the file as ndarray and perform np.min with a given axis:
import numpy as np
arr = np.loadtxt('your_file.csv')
# for each column
minima_c = np.min(arr, axis=0)
# for each row
minima_r = np.min(arr, axis=1)
Here's a little illustration:
In [1]: import numpy as np
In [2]: arr = np.arange(9).reshape((3,3))
In [3]: arr
Out[3]: 
array([[0, 1, 2],
       [3, 4, 5],
       [6, 7, 8]])
In [4]: np.min(arr, 0)
Out[4]: array([0, 1, 2])
In [5]: np.min(arr, 1)
Out[5]: array([0, 3, 6])
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